Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …100100010101101001100011 |
3 | 112102111212001202010110121202 |
4 | 121000312303210111221203 |
5 | 103404401000024444341 |
6 | 1025545522332511415 |
7 | 32112650413231124 |
oct | 3100666344255143 |
9 | 472455052113552 |
10 | 110010009999971 |
11 | 32063a8a765344 |
12 | 1040881591b56b |
13 | 494cb90080473 |
14 | 1d2472754804b |
15 | cab92d3e879b |
hex | 640db3915a63 |
110010009999971 has 2 divisors, whose sum is σ = 110010009999972. Its totient is φ = 110010009999970.
The previous prime is 110010009999959. The next prime is 110010010000003. The reversal of 110010009999971 is 179999900010011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110010009999971 - 230 = 110008936258147 is a prime.
It is not a weakly prime, because it can be changed into another prime (110010009999931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005004999985 + 55005004999986.
It is an arithmetic number, because the mean of its divisors is an integer number (55005004999986).
Almost surely, 2110010009999971 is an apocalyptic number.
110010009999971 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010009999971 is an equidigital number, since it uses as much as digits as its factorization.
110010009999971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 413343, while the sum is 56.
The spelling of 110010009999971 in words is "one hundred ten trillion, ten billion, nine million, nine hundred ninety-nine thousand, nine hundred seventy-one".
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