Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …101000001001110011111011 |
3 | 112102111212001211000021111001 |
4 | 121000312303220021303323 |
5 | 103404401000304000214 |
6 | 1025545522410145431 |
7 | 32112650424564622 |
oct | 3100666350116373 |
9 | 472455054007431 |
10 | 110010011000059 |
11 | 32063a90288765 |
12 | 10408816122277 |
13 | 494cb90340731 |
14 | 1d247277286b9 |
15 | cab92d544c74 |
hex | 640db3a09cfb |
110010011000059 has 2 divisors, whose sum is σ = 110010011000060. Its totient is φ = 110010011000058.
The previous prime is 110010011000047. The next prime is 110010011000173. The reversal of 110010011000059 is 950000110010011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110010011000059 - 25 = 110010011000027 is a prime.
It is a super-3 number, since 3×1100100110000593 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (110010011000759) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005005500029 + 55005005500030.
It is an arithmetic number, because the mean of its divisors is an integer number (55005005500030).
Almost surely, 2110010011000059 is an apocalyptic number.
110010011000059 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010011000059 is an equidigital number, since it uses as much as digits as its factorization.
110010011000059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 19.
The spelling of 110010011000059 in words is "one hundred ten trillion, ten billion, eleven million, fifty-nine", and thus it is an aban number.
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