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110010020223 = 336670006741
BaseRepresentation
bin110011001110100011…
…0111011000101111111
3101111221210021001112110
41212131012323011333
53300300031121343
6122312104305103
710643102512635
oct1463506730577
9344853231473
10110010020223
1142722874494
12193a2172193
13a4b25c7a2c
145478671355
152cdce26833
hex199d1bb17f

110010020223 has 4 divisors (see below), whose sum is σ = 146680026968. Its totient is φ = 73340013480.

The previous prime is 110010020189. The next prime is 110010020231. The reversal of 110010020223 is 322020010011.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 110010020223 - 216 = 110009954687 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110010020199 and 110010020208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110010020243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18335003368 + ... + 18335003373.

It is an arithmetic number, because the mean of its divisors is an integer number (36670006742).

Almost surely, 2110010020223 is an apocalyptic number.

110010020223 is a deficient number, since it is larger than the sum of its proper divisors (36670006745).

110010020223 is an equidigital number, since it uses as much as digits as its factorization.

110010020223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36670006744.

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 110010020223 its reverse (322020010011), we get a palindrome (432030030234).

The spelling of 110010020223 in words is "one hundred ten billion, ten million, twenty thousand, two hundred twenty-three".

Divisors: 1 3 36670006741 110010020223