110010053401 has 2 divisors, whose sum is σ = 110010053402. Its totient is φ = 110010053400.

The previous prime is 110010053383. The next prime is 110010053407. The reversal of 110010053401 is 104350010011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109547760400 + 462293001 = 330980^2 + 21501^2 .

It is a cyclic number.

It is not a de Polignac number, because 110010053401 - 2¹⁷ = 110009922329 is a prime.

It is not a weakly prime, because it can be changed into another prime (110010053407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005026700 + 55005026701.

It is an arithmetic number, because the mean of its divisors is an integer number (55005026701).

Almost surely, 2^110010053401 is an apocalyptic number.

It is an amenable number.

110010053401 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010053401 is an equidigital number, since it uses as much as digits as its factorization.

110010053401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 110010053401 its reverse (104350010011), we get a palindrome (214360063412).

The spelling of 110010053401 in words is "one hundred ten billion, ten million, fifty-three thousand, four hundred one".