Base | Representation |
---|---|
bin | 11001000000110110111001… |
… | …100001110011111101000011 |
3 | 112102111212022201022001012012 |
4 | 121000312321201303331003 |
5 | 103404401201130012323 |
6 | 1025545540304123135 |
7 | 32112653036226164 |
oct | 3100667141637503 |
9 | 472455281261165 |
10 | 110010110000963 |
11 | 32064031157597 |
12 | 104088433064ab |
13 | 494cba79c4553 |
14 | 1d2473693976b |
15 | cab93709d678 |
hex | 640db9873f43 |
110010110000963 has 2 divisors, whose sum is σ = 110010110000964. Its totient is φ = 110010110000962.
The previous prime is 110010110000941. The next prime is 110010110001061. The reversal of 110010110000963 is 369000011010011.
It is a weak prime.
It is an emirp because it is prime and its reverse (369000011010011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110010110000963 - 212 = 110010109996867 is a prime.
It is not a weakly prime, because it can be changed into another prime (110010110000933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005055000481 + 55005055000482.
It is an arithmetic number, because the mean of its divisors is an integer number (55005055000482).
Almost surely, 2110010110000963 is an apocalyptic number.
110010110000963 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010110000963 is an equidigital number, since it uses as much as digits as its factorization.
110010110000963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 23.
Adding to 110010110000963 its reverse (369000011010011), we get a palindrome (479010121010974).
The spelling of 110010110000963 in words is "one hundred ten trillion, ten billion, one hundred ten million, nine hundred sixty-three", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •