Base | Representation |
---|---|
bin | 11001000000110110111001… |
… | …100010100100010010101001 |
3 | 112102111212022201200002210011 |
4 | 121000312321202210102221 |
5 | 103404401201202331303 |
6 | 1025545540312251521 |
7 | 32112653041012336 |
oct | 3100667142442251 |
9 | 472455281602704 |
10 | 110010110198953 |
11 | 32064031282318 |
12 | 104088433a0ba1 |
13 | 494cba7a636c3 |
14 | 1d2473698b98d |
15 | cab9370dc16d |
hex | 640db98a44a9 |
110010110198953 has 2 divisors, whose sum is σ = 110010110198954. Its totient is φ = 110010110198952.
The previous prime is 110010110198939. The next prime is 110010110199001. The reversal of 110010110198953 is 359891011010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109572596742249 + 437513456704 = 10467693^2 + 661448^2 .
It is a cyclic number.
It is not a de Polignac number, because 110010110198953 - 229 = 110009573328041 is a prime.
It is not a weakly prime, because it can be changed into another prime (110010110198453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005055099476 + 55005055099477.
It is an arithmetic number, because the mean of its divisors is an integer number (55005055099477).
Almost surely, 2110010110198953 is an apocalyptic number.
It is an amenable number.
110010110198953 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010110198953 is an equidigital number, since it uses as much as digits as its factorization.
110010110198953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 40.
The spelling of 110010110198953 in words is "one hundred ten trillion, ten billion, one hundred ten million, one hundred ninety-eight thousand, nine hundred fifty-three".
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