Base | Representation |
---|---|
bin | 1010000000010101111101… |
… | …1011001111000011101011 |
3 | 1102221200112110022210022012 |
4 | 2200011133123033003223 |
5 | 2420220033112021024 |
6 | 35221443434550135 |
7 | 2213540224001414 |
oct | 240053733170353 |
9 | 42850473283265 |
10 | 11001012220139 |
11 | 3561559669987 |
12 | 12980a089834b |
13 | 61a51104c496 |
14 | 2a0647b8480b |
15 | 1412654a150e |
hex | a015f6cf0eb |
11001012220139 has 2 divisors, whose sum is σ = 11001012220140. Its totient is φ = 11001012220138.
The previous prime is 11001012220111. The next prime is 11001012220169. The reversal of 11001012220139 is 93102221010011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11001012220139 is a prime.
It is not a weakly prime, because it can be changed into another prime (11001012220169) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500506110069 + 5500506110070.
It is an arithmetic number, because the mean of its divisors is an integer number (5500506110070).
Almost surely, 211001012220139 is an apocalyptic number.
11001012220139 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001012220139 is an equidigital number, since it uses as much as digits as its factorization.
11001012220139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 11001012220139 in words is "eleven trillion, one billion, twelve million, two hundred twenty thousand, one hundred thirty-nine".
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