110010201120217 has 2 divisors, whose sum is σ = 110010201120218. Its totient is φ = 110010201120216.

The previous prime is 110010201120109. The next prime is 110010201120251. The reversal of 110010201120217 is 712021102010011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68971878914761 + 41038322205456 = 8304931^2 + 6406116^2 .

It is a cyclic number.

It is not a de Polignac number, because 110010201120217 - 2⁴³ = 101214108098009 is a prime.

It is a super-2 number, since 2×110010201120217² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110010201120194 and 110010201120203.

It is not a weakly prime, because it can be changed into another prime (110010201120317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005100560108 + 55005100560109.

It is an arithmetic number, because the mean of its divisors is an integer number (55005100560109).

Almost surely, 2^{110010201120217} is an apocalyptic number.

It is an amenable number.

110010201120217 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010201120217 is an equidigital number, since it uses as much as digits as its factorization.

110010201120217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 110010201120217 its reverse (712021102010011), we get a palindrome (822031303130228).

The spelling of 110010201120217 in words is "one hundred ten trillion, ten billion, two hundred one million, one hundred twenty thousand, two hundred seventeen".