Base | Representation |
---|---|
bin | 1010000000010110000000… |
… | …0001101111001000101011 |
3 | 1102221200120011022120002222 |
4 | 2200011200001233020223 |
5 | 2420220043203004003 |
6 | 35221444435144255 |
7 | 2213540405535602 |
oct | 240054001571053 |
9 | 42850504276088 |
10 | 11001022313003 |
11 | 3561564332898 |
12 | 12980a414508b |
13 | 61a5131743a8 |
14 | 2a0649250a39 |
15 | 1412662e6c38 |
hex | a016006f22b |
11001022313003 has 2 divisors, whose sum is σ = 11001022313004. Its totient is φ = 11001022313002.
The previous prime is 11001022312991. The next prime is 11001022313119. The reversal of 11001022313003 is 30031322010011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001022313003 - 236 = 10932302836267 is a prime.
It is a super-2 number, since 2×110010223130032 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11001022318003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500511156501 + 5500511156502.
It is an arithmetic number, because the mean of its divisors is an integer number (5500511156502).
Almost surely, 211001022313003 is an apocalyptic number.
11001022313003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001022313003 is an equidigital number, since it uses as much as digits as its factorization.
11001022313003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 11001022313003 its reverse (30031322010011), we get a palindrome (41032344323014).
The spelling of 11001022313003 in words is "eleven trillion, one billion, twenty-two million, three hundred thirteen thousand, three".
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