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1100103231113 is a prime number
BaseRepresentation
bin10000000000100011010…
…000110010011010001001
310220011120002022110012022
4100000203100302122021
5121011002411343423
62201214102054225
7142323404114615
oct20004320623211
93804502273168
101100103231113
1139460765a067
1215925a41a375
137c97c2b0683
143b36109a345
151d939a92dc8
hex10023432689

1100103231113 has 2 divisors, whose sum is σ = 1100103231114. Its totient is φ = 1100103231112.

The previous prime is 1100103231041. The next prime is 1100103231119. The reversal of 1100103231113 is 3111323010011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 994561414729 + 105541816384 = 997277^2 + 324872^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100103231113 - 28 = 1100103230857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100103231091 and 1100103231100.

It is not a weakly prime, because it can be changed into another prime (1100103231119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550051615556 + 550051615557.

It is an arithmetic number, because the mean of its divisors is an integer number (550051615557).

Almost surely, 21100103231113 is an apocalyptic number.

It is an amenable number.

1100103231113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100103231113 is an equidigital number, since it uses as much as digits as its factorization.

1100103231113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1100103231113 its reverse (3111323010011), we get a palindrome (4211426241124).

The spelling of 1100103231113 in words is "one trillion, one hundred billion, one hundred three million, two hundred thirty-one thousand, one hundred thirteen".