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1100103299999 = 11100009390909
BaseRepresentation
bin10000000000100011010…
…001000011001110011111
310220011120002102221200122
4100000203101003032133
5121011002421044444
62201214103345155
7142323404522504
oct20004321031637
93804502387618
101100103299999
113946076a68a0
1215925a4521bb
137c97c305b32
143b3610b74ab
151d939aa84ee
hex1002344339f

1100103299999 has 4 divisors (see below), whose sum is σ = 1200112690920. Its totient is φ = 1000093909080.

The previous prime is 1100103299993. The next prime is 1100103300007. The reversal of 1100103299999 is 9999923010011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100103299999 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1100103299999.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100103299993) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50004695444 + ... + 50004695465.

It is an arithmetic number, because the mean of its divisors is an integer number (300028172730).

Almost surely, 21100103299999 is an apocalyptic number.

1100103299999 is a deficient number, since it is larger than the sum of its proper divisors (100009390921).

1100103299999 is a wasteful number, since it uses less digits than its factorization.

1100103299999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100009390920.

The product of its (nonzero) digits is 354294, while the sum is 53.

The spelling of 1100103299999 in words is "one trillion, one hundred billion, one hundred three million, two hundred ninety-nine thousand, nine hundred ninety-nine".

Divisors: 1 11 100009390909 1100103299999