Base | Representation |
---|---|
bin | 10000000000100011010… |
… | …001100011010010100101 |
3 | 10220011120002200121211212 |
4 | 100000203101203102211 |
5 | 121011002434300313 |
6 | 2201214110241205 |
7 | 142323405610424 |
oct | 20004321432245 |
9 | 3804502617755 |
10 | 1100103431333 |
11 | 394607786535 |
12 | 15925a4b6205 |
13 | 7c97c35084a |
14 | 3b36110d2bb |
15 | 1d939ad23a8 |
hex | 100234634a5 |
1100103431333 has 16 divisors (see below), whose sum is σ = 1233600762240. Its totient is φ = 975592713216.
The previous prime is 1100103431309. The next prime is 1100103431359. The reversal of 1100103431333 is 3331343010011.
It is a cyclic number.
It is not a de Polignac number, because 1100103431333 - 216 = 1100103365797 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a junction number, because it is equal to n+sod(n) for n = 1100103431299 and 1100103431308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100103431363) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20970548 + ... + 21022941.
It is an arithmetic number, because the mean of its divisors is an integer number (77100047640).
Almost surely, 21100103431333 is an apocalyptic number.
It is an amenable number.
1100103431333 is a deficient number, since it is larger than the sum of its proper divisors (133497330907).
1100103431333 is a wasteful number, since it uses less digits than its factorization.
1100103431333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41993596.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 1100103431333 its reverse (3331343010011), we get a palindrome (4431446441344).
The spelling of 1100103431333 in words is "one trillion, one hundred billion, one hundred three million, four hundred thirty-one thousand, three hundred thirty-three".
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