Base | Representation |
---|---|
bin | 10000000000100011010… |
… | …100111000000110000001 |
3 | 10220011120011022220111222 |
4 | 100000203110320012001 |
5 | 121011003200143402 |
6 | 2201214141044425 |
7 | 142323416200601 |
oct | 20004324700601 |
9 | 3804504286458 |
10 | 1100104302977 |
11 | 3946082213a9 |
12 | 15925a856715 |
13 | 7c97c597504 |
14 | 3b361298c01 |
15 | 1d939c057a2 |
hex | 10023538181 |
1100104302977 has 2 divisors, whose sum is σ = 1100104302978. Its totient is φ = 1100104302976.
The previous prime is 1100104302961. The next prime is 1100104303009. The reversal of 1100104302977 is 7792034010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1090595907856 + 9508395121 = 1044316^2 + 97511^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100104302977 - 24 = 1100104302961 is a prime.
It is a super-2 number, since 2×11001043029772 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100104302907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550052151488 + 550052151489.
It is an arithmetic number, because the mean of its divisors is an integer number (550052151489).
Almost surely, 21100104302977 is an apocalyptic number.
It is an amenable number.
1100104302977 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100104302977 is an equidigital number, since it uses as much as digits as its factorization.
1100104302977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10584, while the sum is 35.
Adding to 1100104302977 its reverse (7792034010011), we get a palindrome (8892138312988).
The spelling of 1100104302977 in words is "one trillion, one hundred billion, one hundred four million, three hundred two thousand, nine hundred seventy-seven".
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