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110010933952147 is a prime number
BaseRepresentation
bin11001000000110111101010…
…101000111011111010010011
3112102111221110010201002201201
4121000313222220323322103
5103404404343042432042
61025550154140212031
732113012332546214
oct3100675250737223
9472457403632651
10110010933952147
1132064414267288
1210408a3323a017
13494cca9612127
141d247b413b40b
15cab9845a71b7
hex640deaa3be93

110010933952147 has 2 divisors, whose sum is σ = 110010933952148. Its totient is φ = 110010933952146.

The previous prime is 110010933952057. The next prime is 110010933952151. The reversal of 110010933952147 is 741259339010011.

It is a strong prime.

It is an emirp because it is prime and its reverse (741259339010011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110010933952147 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110010933952097 and 110010933952106.

It is not a weakly prime, because it can be changed into another prime (110010933052147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005466976073 + 55005466976074.

It is an arithmetic number, because the mean of its divisors is an integer number (55005466976074).

Almost surely, 2110010933952147 is an apocalyptic number.

110010933952147 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010933952147 is an equidigital number, since it uses as much as digits as its factorization.

110010933952147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 204120, while the sum is 46.

The spelling of 110010933952147 in words is "one hundred ten trillion, ten billion, nine hundred thirty-three million, nine hundred fifty-two thousand, one hundred forty-seven".