Base | Representation |
---|---|
bin | 1010000000010110010010… |
… | …1010000101101100101011 |
3 | 1102221200202120111110200202 |
4 | 2200011210222011230223 |
5 | 2420220223100000133 |
6 | 35221500252222415 |
7 | 2213542341056456 |
oct | 240054452055453 |
9 | 42850676443622 |
10 | 11001100000043 |
11 | 35615a417425a |
12 | 129810616aa0b |
13 | 61a5262a4a5a |
14 | 2a06556b449d |
15 | 14126d0402e8 |
hex | a0164a85b2b |
11001100000043 has 2 divisors, whose sum is σ = 11001100000044. Its totient is φ = 11001100000042.
The previous prime is 11001099999977. The next prime is 11001100000067. The reversal of 11001100000043 is 34000000110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11001100000043 - 220 = 11001098951467 is a prime.
It is not a weakly prime, because it can be changed into another prime (11001100000243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500550000021 + 5500550000022.
It is an arithmetic number, because the mean of its divisors is an integer number (5500550000022).
Almost surely, 211001100000043 is an apocalyptic number.
11001100000043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001100000043 is an equidigital number, since it uses as much as digits as its factorization.
11001100000043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 11001100000043 its reverse (34000000110011), we get a palindrome (45001100110054).
The spelling of 11001100000043 in words is "eleven trillion, one billion, one hundred million, forty-three", and thus it is an aban number.
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