Base | Representation |
---|---|
bin | 11001000000110111101111… |
… | …010011100000010101000011 |
3 | 112102111221122120222112100111 |
4 | 121000313233103200111003 |
5 | 103404410023112021402 |
6 | 1025550210013532151 |
7 | 32113014303040066 |
oct | 3100675723402503 |
9 | 472457576875314 |
10 | 110011012220227 |
11 | 32064454465248 |
12 | 10408a554a4057 |
13 | 494ccbc8b70c1 |
14 | 1d247c06b28dd |
15 | cab98b3b79d7 |
hex | 640def4e0543 |
110011012220227 has 2 divisors, whose sum is σ = 110011012220228. Its totient is φ = 110011012220226.
The previous prime is 110011012220149. The next prime is 110011012220257. The reversal of 110011012220227 is 722022210110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110011012220227 - 219 = 110011011695939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110011012220198 and 110011012220207.
It is not a weakly prime, because it can be changed into another prime (110011012220257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005506110113 + 55005506110114.
It is an arithmetic number, because the mean of its divisors is an integer number (55005506110114).
Almost surely, 2110011012220227 is an apocalyptic number.
110011012220227 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011012220227 is an equidigital number, since it uses as much as digits as its factorization.
110011012220227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 110011012220227 its reverse (722022210110011), we get a palindrome (832033222330238).
The spelling of 110011012220227 in words is "one hundred ten trillion, eleven billion, twelve million, two hundred twenty thousand, two hundred twenty-seven".
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