Base | Representation |
---|---|
bin | 11001000000110111110100… |
… | …101010110010110000101001 |
3 | 112102111221212212022112122021 |
4 | 121000313310222302300221 |
5 | 103404410214131223423 |
6 | 1025550222550424441 |
7 | 32113016444664145 |
oct | 3100676452626051 |
9 | 472457785275567 |
10 | 110011102211113 |
11 | 320644a023a784 |
12 | 10408a7b662121 |
13 | 4950005434b4c |
14 | 1d247cc61a225 |
15 | cab99424195d |
hex | 640df4ab2c29 |
110011102211113 has 2 divisors, whose sum is σ = 110011102211114. Its totient is φ = 110011102211112.
The previous prime is 110011102211107. The next prime is 110011102211141. The reversal of 110011102211113 is 311112201110011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 58412208412944 + 51598893798169 = 7642788^2 + 7183237^2 .
It is a cyclic number.
It is not a de Polignac number, because 110011102211113 - 29 = 110011102210601 is a prime.
It is not a weakly prime, because it can be changed into another prime (110011102211173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005551105556 + 55005551105557.
It is an arithmetic number, because the mean of its divisors is an integer number (55005551105557).
Almost surely, 2110011102211113 is an apocalyptic number.
It is an amenable number.
110011102211113 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011102211113 is an equidigital number, since it uses as much as digits as its factorization.
110011102211113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 16.
Adding to 110011102211113 its reverse (311112201110011), we get a palindrome (421123303321124).
The spelling of 110011102211113 in words is "one hundred ten trillion, eleven billion, one hundred two million, two hundred eleven thousand, one hundred thirteen".
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