Base | Representation |
---|---|
bin | 1010000000010110010101… |
… | …0100110100000011110011 |
3 | 1102221200210100120111010111 |
4 | 2200011211110310003303 |
5 | 2420220233431344422 |
6 | 35221501332242151 |
7 | 2213542535214406 |
oct | 240054524640363 |
9 | 42850710514114 |
10 | 11001111199987 |
11 | 35615aa523a07 |
12 | 1298109a70357 |
13 | 61a5286c683c |
14 | 2a0656d8bd3d |
15 | 14126e003a77 |
hex | a01655340f3 |
11001111199987 has 2 divisors, whose sum is σ = 11001111199988. Its totient is φ = 11001111199986.
The previous prime is 11001111199933. The next prime is 11001111200039. The reversal of 11001111199987 is 78999111110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11001111199987 - 235 = 10966751461619 is a prime.
It is a super-2 number, since 2×110011111999872 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11001111199987.
It is not a weakly prime, because it can be changed into another prime (11001111199387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555599993 + 5500555599994.
It is an arithmetic number, because the mean of its divisors is an integer number (5500555599994).
Almost surely, 211001111199987 is an apocalyptic number.
11001111199987 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001111199987 is an equidigital number, since it uses as much as digits as its factorization.
11001111199987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 49.
The spelling of 11001111199987 in words is "eleven trillion, one billion, one hundred eleven million, one hundred ninety-nine thousand, nine hundred eighty-seven".
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