11001112100113 has 2 divisors, whose sum is σ = 11001112100114. Its totient is φ = 11001112100112.

The previous prime is 11001112100101. The next prime is 11001112100117. The reversal of 11001112100113 is 31100121110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9301694817424 + 1699417282689 = 3049868^2 + 1303617^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001112100113 is a prime.

It is a super-2 number, since 2×11001112100113² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11001112100093 and 11001112100102.

It is not a weakly prime, because it can be changed into another prime (11001112100117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500556050056 + 5500556050057.

It is an arithmetic number, because the mean of its divisors is an integer number (5500556050057).

Almost surely, 2^{11001112100113} is an apocalyptic number.

It is an amenable number.

11001112100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001112100113 is an equidigital number, since it uses as much as digits as its factorization.

11001112100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 11001112100113 its reverse (31100121110011), we get a palindrome (42101233210124).

The spelling of 11001112100113 in words is "eleven trillion, one billion, one hundred twelve million, one hundred thousand, one hundred thirteen".