Base | Representation |
---|---|
bin | 1010000000010110010101… |
… | …1100000111011010011011 |
3 | 1102221200210111011202000202 |
4 | 2200011211130013122123 |
5 | 2420220234424124032 |
6 | 35221501441252415 |
7 | 2213542560406403 |
oct | 240054534073233 |
9 | 42850714152022 |
10 | 11001113114267 |
11 | 3561600611161 |
12 | 129810a63410b |
13 | 61a528c16c53 |
14 | 2a0657329803 |
15 | 14126e280d62 |
hex | a016570769b |
11001113114267 has 2 divisors, whose sum is σ = 11001113114268. Its totient is φ = 11001113114266.
The previous prime is 11001113114261. The next prime is 11001113114339. The reversal of 11001113114267 is 76241131110011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001113114267 - 26 = 11001113114203 is a prime.
It is a super-3 number, since 3×110011131142673 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11001113114261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500556557133 + 5500556557134.
It is an arithmetic number, because the mean of its divisors is an integer number (5500556557134).
Almost surely, 211001113114267 is an apocalyptic number.
11001113114267 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001113114267 is an equidigital number, since it uses as much as digits as its factorization.
11001113114267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 29.
Adding to 11001113114267 its reverse (76241131110011), we get a palindrome (87242244224278).
The spelling of 11001113114267 in words is "eleven trillion, one billion, one hundred thirteen million, one hundred fourteen thousand, two hundred sixty-seven".
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