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11001120323 is a prime number
BaseRepresentation
bin10100011111011011…
…11100011001000011
31001101200112211000212
422033231330121003
5140012241322243
65015344104335
7536421660044
oct121755743103
931350484025
1011001120323
114735933586
1221703050ab
13106422a56b
147650c28cb
15445c11318
hex28fb7c643

11001120323 has 2 divisors, whose sum is σ = 11001120324. Its totient is φ = 11001120322.

The previous prime is 11001120313. The next prime is 11001120329. The reversal of 11001120323 is 32302110011.

It is a strong prime.

It is an emirp because it is prime and its reverse (32302110011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001120323 - 24 = 11001120307 is a prime.

It is a super-2 number, since 2×110011203232 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11001120298 and 11001120307.

It is not a weakly prime, because it can be changed into another prime (11001120329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500560161 + 5500560162.

It is an arithmetic number, because the mean of its divisors is an integer number (5500560162).

Almost surely, 211001120323 is an apocalyptic number.

11001120323 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001120323 is an equidigital number, since it uses as much as digits as its factorization.

11001120323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 11001120323 its reverse (32302110011), we get a palindrome (43303230334).

The spelling of 11001120323 in words is "eleven billion, one million, one hundred twenty thousand, three hundred twenty-three".