Base | Representation |
---|---|
bin | 10000000000100011110… |
… | …110100000111101100011 |
3 | 10220011120202220220201222 |
4 | 100000203312200331203 |
5 | 121011012424333443 |
6 | 2201215054045255 |
7 | 142323554145512 |
oct | 20004366407543 |
9 | 3804522826658 |
10 | 1100113121123 |
11 | 3946121a4625 |
12 | 1592617a982b |
13 | 7c981364153 |
14 | 3b362512679 |
15 | 1d93a898468 |
hex | 10023da0f63 |
1100113121123 has 2 divisors, whose sum is σ = 1100113121124. Its totient is φ = 1100113121122.
The previous prime is 1100113121111. The next prime is 1100113121131. The reversal of 1100113121123 is 3211213110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100113121123 - 218 = 1100112858979 is a prime.
It is a super-2 number, since 2×11001131211232 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100113121323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550056560561 + 550056560562.
It is an arithmetic number, because the mean of its divisors is an integer number (550056560562).
Almost surely, 21100113121123 is an apocalyptic number.
1100113121123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100113121123 is an equidigital number, since it uses as much as digits as its factorization.
1100113121123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 1100113121123 its reverse (3211213110011), we get a palindrome (4311326231134).
The spelling of 1100113121123 in words is "one trillion, one hundred billion, one hundred thirteen million, one hundred twenty-one thousand, one hundred twenty-three".
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