Base | Representation |
---|---|
bin | 11001000000111000110000… |
… | …001101101001000010110111 |
3 | 112102112001110111002112122120 |
4 | 121000320300031221002313 |
5 | 103404414240401431403 |
6 | 1025550510034331023 |
7 | 32113053265163262 |
oct | 3100706015510267 |
9 | 472461414075576 |
10 | 110012101202103 |
11 | 32064963134471 |
12 | 104090ba129a73 |
13 | 49501343aa989 |
14 | 1d24885183cd9 |
15 | caba01cc3e53 |
hex | 640e303690b7 |
110012101202103 has 16 divisors (see below), whose sum is σ = 151757835899520. Its totient is φ = 70804450541664.
The previous prime is 110012101202071. The next prime is 110012101202221. The reversal of 110012101202103 is 301202101210011.
It is not a de Polignac number, because 110012101202103 - 25 = 110012101202071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110012101202503) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 70080301 + ... + 71632902.
It is an arithmetic number, because the mean of its divisors is an integer number (9484864743720).
Almost surely, 2110012101202103 is an apocalyptic number.
110012101202103 is a deficient number, since it is larger than the sum of its proper divisors (41745734697417).
110012101202103 is a wasteful number, since it uses less digits than its factorization.
110012101202103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 141722158.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 110012101202103 its reverse (301202101210011), we get a palindrome (411214202412114).
The spelling of 110012101202103 in words is "one hundred ten trillion, twelve billion, one hundred one million, two hundred two thousand, one hundred three".
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