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110012111002 = 267820985903
BaseRepresentation
bin110011001110100111…
…0111001100010011010
3101111221221012021112201
41212131032321202122
53300301100023002
6122312221200414
710643126341333
oct1463516714232
9344857167481
10110012111002
1142723a72302
12193a2a0010a
13a4b2b7a591
145478a5728a
152cdd1db087
hex199d3b989a

110012111002 has 8 divisors (see below), whose sum is σ = 167481124416. Its totient is φ = 54185069532.

The previous prime is 110012110997. The next prime is 110012111023. The reversal of 110012111002 is 200111210011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×1100121110023 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 110012111002.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 410492818 + ... + 410493085.

It is an arithmetic number, because the mean of its divisors is an integer number (20935140552).

Almost surely, 2110012111002 is an apocalyptic number.

110012111002 is a deficient number, since it is larger than the sum of its proper divisors (57469013414).

110012111002 is an equidigital number, since it uses as much as digits as its factorization.

110012111002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 820985972.

The product of its (nonzero) digits is 4, while the sum is 10.

Adding to 110012111002 its reverse (200111210011), we get a palindrome (310123321013).

Subtracting 110012111002 from its reverse (200111210011), we obtain a palindrome (90099099009).

The spelling of 110012111002 in words is "one hundred ten billion, twelve million, one hundred eleven thousand, two".

Divisors: 1 2 67 134 820985903 1641971806 55006055501 110012111002