1100121130313 has 2 divisors, whose sum is σ = 1100121130314. Its totient is φ = 1100121130312.

The previous prime is 1100121130301. The next prime is 1100121130343. The reversal of 1100121130313 is 3130311210011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 814491810064 + 285629320249 = 902492^2 + 534443^2 .

It is an emirp because it is prime and its reverse (3130311210011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100121130313 - 2¹² = 1100121126217 is a prime.

It is a super-2 number, since 2×1100121130313² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100121130291 and 1100121130300.

It is not a weakly prime, because it can be changed into another prime (1100121130343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550060565156 + 550060565157.

It is an arithmetic number, because the mean of its divisors is an integer number (550060565157).

Almost surely, 2^{1100121130313} is an apocalyptic number.

It is an amenable number.

1100121130313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100121130313 is an equidigital number, since it uses as much as digits as its factorization.

1100121130313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1100121130313 its reverse (3130311210011), we get a palindrome (4230432340324).

The spelling of 1100121130313 in words is "one trillion, one hundred billion, one hundred twenty-one million, one hundred thirty thousand, three hundred thirteen".