11001213220023 has 24 divisors (see below), whose sum is σ = 17114078268560. Its totient is φ = 6769550142720.

The previous prime is 11001213219979. The next prime is 11001213220099. The reversal of 11001213220023 is 32002231210011.

It is not a de Polignac number, because 11001213220023 - 2²¹ = 11001211122871 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11001213219978 and 11001213220005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001213220423) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1099873 + ... + 4817898.

Almost surely, 2^{11001213220023} is an apocalyptic number.

11001213220023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11001213220023 is a deficient number, since it is larger than the sum of its proper divisors (6112865048537).

11001213220023 is a wasteful number, since it uses less digits than its factorization.

11001213220023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5933679 (or 5933676 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 11001213220023 its reverse (32002231210011), we get a palindrome (43003444430034).

The spelling of 11001213220023 in words is "eleven trillion, one billion, two hundred thirteen million, two hundred twenty thousand, twenty-three".