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110012222113 is a prime number
BaseRepresentation
bin110011001110100111…
…1010100101010100001
3101111221221101220221221
41212131033110222201
53300301112101423
6122312223415041
710643130313303
oct1463517245241
9344857356857
10110012222113
1142724038832
12193a2a54481
13a4b2bb9021
145478a85973
152cdd20de5d
hex199d3d4aa1

110012222113 has 2 divisors, whose sum is σ = 110012222114. Its totient is φ = 110012222112.

The previous prime is 110012222083. The next prime is 110012222147. The reversal of 110012222113 is 311222210011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 62404036864 + 47608185249 = 249808^2 + 218193^2 .

It is a cyclic number.

It is not a de Polignac number, because 110012222113 - 213 = 110012213921 is a prime.

It is not a weakly prime, because it can be changed into another prime (110012222713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006111056 + 55006111057.

It is an arithmetic number, because the mean of its divisors is an integer number (55006111057).

Almost surely, 2110012222113 is an apocalyptic number.

It is an amenable number.

110012222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110012222113 is an equidigital number, since it uses as much as digits as its factorization.

110012222113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 110012222113 its reverse (311222210011), we get a palindrome (421234432124).

The spelling of 110012222113 in words is "one hundred ten billion, twelve million, two hundred twenty-two thousand, one hundred thirteen".