Base | Representation |
---|---|
bin | 1010000000010110110010… |
… | …0110101101101111100101 |
3 | 1102221201002212101111102121 |
4 | 2200011230212231233211 |
5 | 2420221011213130341 |
6 | 35221521414105541 |
7 | 2213545550302105 |
oct | 240055446555745 |
9 | 42851085344377 |
10 | 11001233333221 |
11 | 356166246246a |
12 | 129814294b2b1 |
13 | 61a547ab9721 |
14 | 2a06692a1205 |
15 | 141279acb4d1 |
hex | a016c9adbe5 |
11001233333221 has 4 divisors (see below), whose sum is σ = 11187694915200. Its totient is φ = 10814771751244.
The previous prime is 11001233333219. The next prime is 11001233333249. The reversal of 11001233333221 is 12233333210011.
11001233333221 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11001233333221 - 21 = 11001233333219 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11001233333021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93230790901 + ... + 93230791018.
It is an arithmetic number, because the mean of its divisors is an integer number (2796923728800).
Almost surely, 211001233333221 is an apocalyptic number.
It is an amenable number.
11001233333221 is a deficient number, since it is larger than the sum of its proper divisors (186461581979).
11001233333221 is an equidigital number, since it uses as much as digits as its factorization.
11001233333221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 186461581978.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 11001233333221 its reverse (12233333210011), we get a palindrome (23234566543232).
It can be divided in two parts, 1100123 and 3333221, that added together give a palindrome (4433344).
The spelling of 11001233333221 in words is "eleven trillion, one billion, two hundred thirty-three million, three hundred thirty-three thousand, two hundred twenty-one".
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