Base | Representation |
---|---|
bin | 10000000000100100100… |
… | …001101000110010001001 |
3 | 10220011121120012020020011 |
4 | 100000210201220302021 |
5 | 121011023323102403 |
6 | 2201220140231521 |
7 | 142324052216452 |
oct | 20004441506211 |
9 | 3804546166204 |
10 | 1100124425353 |
11 | 394618615668 |
12 | 15926553b5a1 |
13 | 7c9837c1545 |
14 | 3b363c16129 |
15 | 1d93b87ca6d |
hex | 10024868c89 |
1100124425353 has 2 divisors, whose sum is σ = 1100124425354. Its totient is φ = 1100124425352.
The previous prime is 1100124425341. The next prime is 1100124425363. The reversal of 1100124425353 is 3535244210011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1005824456464 + 94299968889 = 1002908^2 + 307083^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100124425353 - 25 = 1100124425321 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100124425363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550062212676 + 550062212677.
It is an arithmetic number, because the mean of its divisors is an integer number (550062212677).
Almost surely, 21100124425353 is an apocalyptic number.
It is an amenable number.
1100124425353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100124425353 is an equidigital number, since it uses as much as digits as its factorization.
1100124425353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1100124425353 its reverse (3535244210011), we get a palindrome (4635368635364).
The spelling of 1100124425353 in words is "one trillion, one hundred billion, one hundred twenty-four million, four hundred twenty-five thousand, three hundred fifty-three".
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