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1100130134541 = 33113371349787
BaseRepresentation
bin10000000000100100110…
…111011010101000001101
310220011121221221021202120
4100000210313122220031
5121011031303301131
62201220502443153
7142324151565354
oct20004467325015
93804557837676
101100130134541
11394620864aa9
121592674334b9
137c984a40069
143b3648a099b
151d93c109496
hex10024ddaa0d

1100130134541 has 16 divisors (see below), whose sum is σ = 1471997449728. Its totient is φ = 730842868400.

The previous prime is 1100130134473. The next prime is 1100130134573. The reversal of 1100130134541 is 1454310310011.

It is a cyclic number.

It is not a de Polignac number, because 1100130134541 - 29 = 1100130134029 is a prime.

It is a super-2 number, since 2×11001301345412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100130134581) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2970250 + ... + 3320036.

It is an arithmetic number, because the mean of its divisors is an integer number (91999840608).

Almost surely, 21100130134541 is an apocalyptic number.

It is an amenable number.

1100130134541 is a deficient number, since it is larger than the sum of its proper divisors (371867315187).

1100130134541 is a wasteful number, since it uses less digits than its factorization.

1100130134541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 353472.

The product of its (nonzero) digits is 720, while the sum is 24.

Adding to 1100130134541 its reverse (1454310310011), we get a palindrome (2554440444552).

The spelling of 1100130134541 in words is "one trillion, one hundred billion, one hundred thirty million, one hundred thirty-four thousand, five hundred forty-one".

Divisors: 1 3 311 933 3371 10113 349787 1048381 1049361 3145143 108783757 326351271 1179131977 3537395931 366710044847 1100130134541