11001306371328 has 864 divisors, whose sum is σ = 40559133468672. Its totient is φ = 2789705318400.

The previous prime is 11001306371299. The next prime is 11001306371329. The reversal of 11001306371328 is 82317360310011.

11001306371328 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 1 + 3 + 0 + 637 + 13 + 2 + 8 = 666.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 11001306371292 and 11001306371301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001306371329) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1020429298 + ... + 1020440078.

Almost surely, 2^{11001306371328} is an apocalyptic number.

11001306371328 is a gapful number since it is divisible by the number (18) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11001306371328, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20279566734336).

11001306371328 is an abundant number, since it is smaller than the sum of its proper divisors (29557827097344).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11001306371328 is a wasteful number, since it uses less digits than its factorization.

11001306371328 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11011 (or 10994 counting only the distinct ones).

The product of its (nonzero) digits is 18144, while the sum is 36.

Adding to 11001306371328 its reverse (82317360310011), we get a palindrome (93318666681339).

The spelling of 11001306371328 in words is "eleven trillion, one billion, three hundred six million, three hundred seventy-one thousand, three hundred twenty-eight".