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11001311161 is a prime number
BaseRepresentation
bin10100011111011101…
…01010111110111001
31001101200220111210221
422033232222332321
5140012313424121
65015352140041
7536423413321
oct121756527671
931350814727
1011001311161
114735a539a5
122170397621
131064296399
14765132281
15445c4cb41
hex28fbaafb9

11001311161 has 2 divisors, whose sum is σ = 11001311162. Its totient is φ = 11001311160.

The previous prime is 11001311129. The next prime is 11001311179. The reversal of 11001311161 is 16111310011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10987022761 + 14288400 = 104819^2 + 3780^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001311161 - 25 = 11001311129 is a prime.

It is a super-4 number, since 4×110013111614 (a number of 41 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (11001311261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500655580 + 5500655581.

It is an arithmetic number, because the mean of its divisors is an integer number (5500655581).

Almost surely, 211001311161 is an apocalyptic number.

It is an amenable number.

11001311161 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001311161 is an equidigital number, since it uses as much as digits as its factorization.

11001311161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 11001311161 its reverse (16111310011), we get a palindrome (27112621172).

The spelling of 11001311161 in words is "eleven billion, one million, three hundred eleven thousand, one hundred sixty-one".