Base | Representation |
---|---|
bin | 10000000000100100111… |
… | …011110111100000011011 |
3 | 10220011122001010120101200 |
4 | 100000210323313200123 |
5 | 121011032103121103 |
6 | 2201220543445243 |
7 | 142324164525321 |
oct | 20004473674033 |
9 | 3804561116350 |
10 | 1100131301403 |
11 | 394621491752 |
12 | 1592678b6823 |
13 | 7c98505b204 |
14 | 3b364ac5d11 |
15 | 1d93c28a0a3 |
hex | 10024ef781b |
1100131301403 has 24 divisors (see below), whose sum is σ = 1597211616000. Its totient is φ = 729667827504.
The previous prime is 1100131301389. The next prime is 1100131301459. The reversal of 1100131301403 is 3041031310011.
1100131301403 is a `hidden beast` number, since 1 + 100 + 131 + 30 + 1 + 403 = 666.
It is not a de Polignac number, because 1100131301403 - 210 = 1100131300379 is a prime.
It is a super-3 number, since 3×11001313014033 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1100131300403) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 25982376 + ... + 26024682.
It is an arithmetic number, because the mean of its divisors is an integer number (66550484000).
Almost surely, 21100131301403 is an apocalyptic number.
1100131301403 is a deficient number, since it is larger than the sum of its proper divisors (497080314597).
1100131301403 is a wasteful number, since it uses less digits than its factorization.
1100131301403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57031 (or 57028 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 1100131301403 its reverse (3041031310011), we get a palindrome (4141162611414).
The spelling of 1100131301403 in words is "one trillion, one hundred billion, one hundred thirty-one million, three hundred one thousand, four hundred three".
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