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1100132100017 is a prime number
BaseRepresentation
bin10000000000100100111…
…110111010011110110001
310220011122002122010212222
4100000210332322132301
5121011032304200032
62201221012530425
7142324204362536
oct20004476723661
93804562563788
101100132100017
11394621987765
12159268020a15
137c98527a872
143b364c52d8d
151d93c396a12
hex10024fba7b1

1100132100017 has 2 divisors, whose sum is σ = 1100132100018. Its totient is φ = 1100132100016.

The previous prime is 1100132099993. The next prime is 1100132100059. The reversal of 1100132100017 is 7100012310011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 580650096016 + 519482004001 = 762004^2 + 720751^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100132100017 - 218 = 1100131837873 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100132099968 and 1100132100004.

It is not a weakly prime, because it can be changed into another prime (1100132100077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550066050008 + 550066050009.

It is an arithmetic number, because the mean of its divisors is an integer number (550066050009).

Almost surely, 21100132100017 is an apocalyptic number.

It is an amenable number.

1100132100017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100132100017 is an equidigital number, since it uses as much as digits as its factorization.

1100132100017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 17.

Adding to 1100132100017 its reverse (7100012310011), we get a palindrome (8200144410028).

The spelling of 1100132100017 in words is "one trillion, one hundred billion, one hundred thirty-two million, one hundred thousand, seventeen".