Base | Representation |
---|---|
bin | 10000000000100100111… |
… | …110111010011111000010 |
3 | 10220011122002122010220121 |
4 | 100000210332322133002 |
5 | 121011032304200114 |
6 | 2201221012530454 |
7 | 142324204362562 |
oct | 20004476723702 |
9 | 3804562563817 |
10 | 1100132100034 |
11 | 394621987780 |
12 | 159268020a2a |
13 | 7c98527a886 |
14 | 3b364c52da2 |
15 | 1d93c396a24 |
hex | 10024fba7c2 |
1100132100034 has 8 divisors (see below), whose sum is σ = 1800216163728. Its totient is φ = 500060045460.
The previous prime is 1100132100017. The next prime is 1100132100059. The reversal of 1100132100034 is 4300012310011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1100132099990 and 1100132100017.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25003002252 + ... + 25003002295.
It is an arithmetic number, because the mean of its divisors is an integer number (225027020466).
Almost surely, 21100132100034 is an apocalyptic number.
1100132100034 is a deficient number, since it is larger than the sum of its proper divisors (700084063694).
1100132100034 is a wasteful number, since it uses less digits than its factorization.
1100132100034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50006004560.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1100132100034 its reverse (4300012310011), we get a palindrome (5400144410045).
The spelling of 1100132100034 in words is "one trillion, one hundred billion, one hundred thirty-two million, one hundred thousand, thirty-four".
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