110013352543341 has 48 divisors (see below), whose sum is σ = 172459621152000. Its totient is φ = 67176898943616.

The previous prime is 110013352543267. The next prime is 110013352543343. The reversal of 110013352543341 is 143345253310011.

110013352543341 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 1 + 33 + 52 + 543 + 34 + 1 = 666.

It is not a de Polignac number, because 110013352543341 - 2²⁶ = 110013285434477 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110013352543296 and 110013352543305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110013352543343) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4023835 + ... + 15369383.

It is an arithmetic number, because the mean of its divisors is an integer number (3592908774000).

Almost surely, 2^{110013352543341} is an apocalyptic number.

It is an amenable number.

110013352543341 is a deficient number, since it is larger than the sum of its proper divisors (62446268608659).

110013352543341 is a wasteful number, since it uses less digits than its factorization.

110013352543341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11346210 (or 11346207 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 36.

The spelling of 110013352543341 in words is "one hundred ten trillion, thirteen billion, three hundred fifty-two million, five hundred forty-three thousand, three hundred forty-one".