Base | Representation |
---|---|
bin | 110011001110101011… |
… | …0000111110001001011 |
3 | 101111222001202110122211 |
4 | 1212131112013301023 |
5 | 3300302041114144 |
6 | 122312325525551 |
7 | 10643151415213 |
oct | 1463526076113 |
9 | 344861673584 |
10 | 110014004299 |
11 | 42725045811 |
12 | 193a35738b7 |
13 | a4b3391284 |
14 | 5478dcb243 |
15 | 2cdd462034 |
hex | 199d587c4b |
110014004299 has 2 divisors, whose sum is σ = 110014004300. Its totient is φ = 110014004298.
The previous prime is 110014004291. The next prime is 110014004311. The reversal of 110014004299 is 992400410011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110014004299 - 23 = 110014004291 is a prime.
It is a super-2 number, since 2×1100140042992 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 110014004299.
It is not a weakly prime, because it can be changed into another prime (110014004291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55007002149 + 55007002150.
It is an arithmetic number, because the mean of its divisors is an integer number (55007002150).
Almost surely, 2110014004299 is an apocalyptic number.
110014004299 is a deficient number, since it is larger than the sum of its proper divisors (1).
110014004299 is an equidigital number, since it uses as much as digits as its factorization.
110014004299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 110014004299 in words is "one hundred ten billion, fourteen million, four thousand, two hundred ninety-nine".
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