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110014112141 = 234783222267
BaseRepresentation
bin110011001110101011…
…0100010000110001101
3101111222001221221120222
41212131112202012031
53300302103042031
6122312332121125
710643152344503
oct1463526420615
9344861857528
10110014112141
114272510983a
12193a36061a5
13a4b33cb39b
145479018673
152cdd483e7b
hex199d5a218d

110014112141 has 4 divisors (see below), whose sum is σ = 114797334432. Its totient is φ = 105230889852.

The previous prime is 110014112123. The next prime is 110014112149. The reversal of 110014112141 is 141211410011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110014112141 - 214 = 110014095757 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110014112149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2391611111 + ... + 2391611156.

It is an arithmetic number, because the mean of its divisors is an integer number (28699333608).

Almost surely, 2110014112141 is an apocalyptic number.

It is an amenable number.

110014112141 is a deficient number, since it is larger than the sum of its proper divisors (4783222291).

110014112141 is an equidigital number, since it uses as much as digits as its factorization.

110014112141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4783222290.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 110014112141 its reverse (141211410011), we get a palindrome (251225522152).

The spelling of 110014112141 in words is "one hundred ten billion, fourteen million, one hundred twelve thousand, one hundred forty-one".

Divisors: 1 23 4783222267 110014112141