11001435314441 has 64 divisors (see below), whose sum is σ = 13589708670720. Its totient is φ = 8768377712640.

The previous prime is 11001435314323. The next prime is 11001435314461. The reversal of 11001435314441 is 14441353410011.

It is a de Polignac number, because none of the positive numbers 2^k-11001435314441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11001435314398 and 11001435314407.

It is not an unprimeable number, because it can be changed into a prime (11001435314461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 80130245 + ... + 80267421.

It is an arithmetic number, because the mean of its divisors is an integer number (212339197980).

Almost surely, 2^{11001435314441} is an apocalyptic number.

11001435314441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11001435314441 is a deficient number, since it is larger than the sum of its proper divisors (2588273356279).

11001435314441 is a wasteful number, since it uses less digits than its factorization.

11001435314441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137546.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 11001435314441 its reverse (14441353410011), we get a palindrome (25442788724452).

The spelling of 11001435314441 in words is "eleven trillion, one billion, four hundred thirty-five million, three hundred fourteen thousand, four hundred forty-one".