1100148014737 has 2 divisors, whose sum is σ = 1100148014738. Its totient is φ = 1100148014736.

The previous prime is 1100148014659. The next prime is 1100148014759. The reversal of 1100148014737 is 7374108410011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 981781740801 + 118366273936 = 990849^2 + 344044^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100148014737 - 2²³ = 1100139626129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100148014696 and 1100148014705.

It is not a weakly prime, because it can be changed into another prime (1100148012737) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550074007368 + 550074007369.

It is an arithmetic number, because the mean of its divisors is an integer number (550074007369).

Almost surely, 2^{1100148014737} is an apocalyptic number.

It is an amenable number.

1100148014737 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100148014737 is an equidigital number, since it uses as much as digits as its factorization.

1100148014737 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18816, while the sum is 37.

The spelling of 1100148014737 in words is "one trillion, one hundred billion, one hundred forty-eight million, fourteen thousand, seven hundred thirty-seven".