11001514331413 has 8 divisors (see below), whose sum is σ = 11166107565600. Its totient is φ = 10836932612880.

The previous prime is 11001514331407. The next prime is 11001514331417. The reversal of 11001514331413 is 31413341510011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11001514331413 - 2¹³ = 11001514323221 is a prime.

It is a super-3 number, since 3×11001514331413³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001514331417) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 944263 + ... + 4784836.

It is an arithmetic number, because the mean of its divisors is an integer number (1395763445700).

Almost surely, 2^{11001514331413} is an apocalyptic number.

It is an amenable number.

11001514331413 is a deficient number, since it is larger than the sum of its proper divisors (164593234187).

11001514331413 is an equidigital number, since it uses as much as digits as its factorization.

11001514331413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5757827.

The product of its (nonzero) digits is 2160, while the sum is 28.

Adding to 11001514331413 its reverse (31413341510011), we get a palindrome (42414855841424).

The spelling of 11001514331413 in words is "eleven trillion, one billion, five hundred fourteen million, three hundred thirty-one thousand, four hundred thirteen".