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11001514331414 = 243127924585249
BaseRepresentation
bin1010000000010111110101…
…0110101000110100010110
31102221201211110010200111002
42200011331112220310112
52420222100132101124
635222005332543302
72213555531610605
oct240057526506426
942851743120432
1011001514331414
113561797038582
121298200a81b32
1361a591093549
142a0694729a3c
151412945d50ae
hexa017d5a8d16

11001514331414 has 8 divisors (see below), whose sum is σ = 16886045253000. Its totient is φ = 5372832580416.

The previous prime is 11001514331407. The next prime is 11001514331417. The reversal of 11001514331414 is 41413341510011.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×110015143314143 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001514331417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63962292539 + ... + 63962292710.

It is an arithmetic number, because the mean of its divisors is an integer number (2110755656625).

Almost surely, 211001514331414 is an apocalyptic number.

11001514331414 is a deficient number, since it is larger than the sum of its proper divisors (5884530921586).

11001514331414 is a wasteful number, since it uses less digits than its factorization.

11001514331414 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 127924585294.

The product of its (nonzero) digits is 2880, while the sum is 29.

Adding to 11001514331414 its reverse (41413341510011), we get a palindrome (52414855841425).

The spelling of 11001514331414 in words is "eleven trillion, one billion, five hundred fourteen million, three hundred thirty-one thousand, four hundred fourteen".

Divisors: 1 2 43 86 127924585249 255849170498 5500757165707 11001514331414