Base | Representation |
---|---|
bin | 1010000000010111110101… |
… | …0110101000110100010110 |
3 | 1102221201211110010200111002 |
4 | 2200011331112220310112 |
5 | 2420222100132101124 |
6 | 35222005332543302 |
7 | 2213555531610605 |
oct | 240057526506426 |
9 | 42851743120432 |
10 | 11001514331414 |
11 | 3561797038582 |
12 | 1298200a81b32 |
13 | 61a591093549 |
14 | 2a0694729a3c |
15 | 1412945d50ae |
hex | a017d5a8d16 |
11001514331414 has 8 divisors (see below), whose sum is σ = 16886045253000. Its totient is φ = 5372832580416.
The previous prime is 11001514331407. The next prime is 11001514331417. The reversal of 11001514331414 is 41413341510011.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×110015143314143 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11001514331417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63962292539 + ... + 63962292710.
It is an arithmetic number, because the mean of its divisors is an integer number (2110755656625).
Almost surely, 211001514331414 is an apocalyptic number.
11001514331414 is a deficient number, since it is larger than the sum of its proper divisors (5884530921586).
11001514331414 is a wasteful number, since it uses less digits than its factorization.
11001514331414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 127924585294.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 11001514331414 its reverse (41413341510011), we get a palindrome (52414855841425).
The spelling of 11001514331414 in words is "eleven trillion, one billion, five hundred fourteen million, three hundred thirty-one thousand, four hundred fourteen".
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