Base | Representation |
---|---|
bin | 11001000001000000000111… |
… | …101011100101110111001010 |
3 | 112102112210212202000010001021 |
4 | 121001000013223211313022 |
5 | 103410031440321401442 |
6 | 1025554254555343054 |
7 | 32113453303325503 |
oct | 3101000753456712 |
9 | 472483782003037 |
10 | 110020011122122 |
11 | 32068252076452 |
12 | 1040a747151a8a |
13 | 4950ac507161a |
14 | 1d24dd58bdbaa |
15 | cabd16428e67 |
hex | 641007ae5dca |
110020011122122 has 4 divisors (see below), whose sum is σ = 165030016683186. Its totient is φ = 55010005561060.
The previous prime is 110020011122089. The next prime is 110020011122123. The reversal of 110020011122122 is 221221110020011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 63391994924281 + 46628016197841 = 7961909^2 + 6828471^2 .
It is a junction number, because it is equal to n+sod(n) for n = 110020011122096 and 110020011122105.
It is not an unprimeable number, because it can be changed into a prime (110020011122123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505002780529 + ... + 27505002780532.
Almost surely, 2110020011122122 is an apocalyptic number.
110020011122122 is a deficient number, since it is larger than the sum of its proper divisors (55010005561064).
110020011122122 is an equidigital number, since it uses as much as digits as its factorization.
110020011122122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55010005561063.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 110020011122122 its reverse (221221110020011), we get a palindrome (331241121142133).
The spelling of 110020011122122 in words is "one hundred ten trillion, twenty billion, eleven million, one hundred twenty-two thousand, one hundred twenty-two".
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