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1100200112002 = 2550100056001
BaseRepresentation
bin10000000000101001000…
…010010110111110000010
310220011210211121111210101
4100000221002112332002
5121011202212041002
62201231442353014
7142325661436315
oct20005102267602
93804724544711
101100200112002
11394657310112
1215928695b76a
137c9963a1544
143b36dcb897c
151d94332d587
hex10029096f82

1100200112002 has 4 divisors (see below), whose sum is σ = 1650300168006. Its totient is φ = 550100056000.

The previous prime is 1100200111963. The next prime is 1100200112023. The reversal of 1100200112002 is 2002110020011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 963988185241 + 136211926761 = 981829^2 + 369069^2 .

It is a super-3 number, since 3×11002001120023 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1100200112002.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275050027999 + ... + 275050028002.

Almost surely, 21100200112002 is an apocalyptic number.

1100200112002 is a deficient number, since it is larger than the sum of its proper divisors (550100056004).

1100200112002 is an equidigital number, since it uses as much as digits as its factorization.

1100200112002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 550100056003.

The product of its (nonzero) digits is 8, while the sum is 10.

Adding to 1100200112002 its reverse (2002110020011), we get a palindrome (3102310132013).

It can be divided in two parts, 110020011 and 2002, that multiplied together give a palindrome (220260062022).

The spelling of 1100200112002 in words is "one trillion, one hundred billion, two hundred million, one hundred twelve thousand, two".

Divisors: 1 2 550100056001 1100200112002