11002011012017 has 2 divisors, whose sum is σ = 11002011012018. Its totient is φ = 11002011012016.

The previous prime is 11002011011989. The next prime is 11002011012037. The reversal of 11002011012017 is 71021011020011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9867947886241 + 1134063125776 = 3141329^2 + 1064924^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11002011012017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11002011011986 and 11002011012004.

It is not a weakly prime, because it can be changed into another prime (11002011012037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501005506008 + 5501005506009.

It is an arithmetic number, because the mean of its divisors is an integer number (5501005506009).

Almost surely, 2^{11002011012017} is an apocalyptic number.

It is an amenable number.

11002011012017 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002011012017 is an equidigital number, since it uses as much as digits as its factorization.

11002011012017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28, while the sum is 17.

Adding to 11002011012017 its reverse (71021011020011), we get a palindrome (82023022032028).

The spelling of 11002011012017 in words is "eleven trillion, two billion, eleven million, twelve thousand, seventeen".