Search a number
-
+
110020111212202 = 255010055606101
BaseRepresentation
bin11001000001000000001101…
…101001011001111010101010
3112102112211010201100012211021
4121001000031221121322222
5103410032141432242302
61025554312532523054
732113455630144352
oct3101001551317252
9472484121305737
10110020111212202
11320682a3619624
121040a77478048a
134950b0ca17119
141d25004cd5b62
15cabd200ea437
hex64100da59eaa

110020111212202 has 4 divisors (see below), whose sum is σ = 165030166818306. Its totient is φ = 55010055606100.

The previous prime is 110020111212149. The next prime is 110020111212227. The reversal of 110020111212202 is 202212111020011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 105949163371921 + 4070947840281 = 10293161^2 + 2017659^2 .

It is a super-2 number, since 2×1100201112122022 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505027803049 + ... + 27505027803052.

Almost surely, 2110020111212202 is an apocalyptic number.

110020111212202 is a deficient number, since it is larger than the sum of its proper divisors (55010055606104).

110020111212202 is an equidigital number, since it uses as much as digits as its factorization.

110020111212202 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55010055606103.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 110020111212202 its reverse (202212111020011), we get a palindrome (312232222232213).

The spelling of 110020111212202 in words is "one hundred ten trillion, twenty billion, one hundred eleven million, two hundred twelve thousand, two hundred two".

Divisors: 1 2 55010055606101 110020111212202