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110020119497833 is a prime number
BaseRepresentation
bin11001000001000000001110…
…001001000000110001101001
3112102112211011021221011120111
4121001000032021000301221
5103410032201042412313
61025554313430254321
732113456060443616
oct3101001611006151
9472484137834514
10110020119497833
11320682a8268756
121040a7774b73a1
134950b1165856c
141d2500605150d
15cabd20bd543d
hex64100e240c69

110020119497833 has 2 divisors, whose sum is σ = 110020119497834. Its totient is φ = 110020119497832.

The previous prime is 110020119497801. The next prime is 110020119497861. The reversal of 110020119497833 is 338794911020011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105387306652224 + 4632812845609 = 10265832^2 + 2152397^2 .

It is a cyclic number.

It is not a de Polignac number, because 110020119497833 - 25 = 110020119497801 is a prime.

It is not a weakly prime, because it can be changed into another prime (110020119407833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010059748916 + 55010059748917.

It is an arithmetic number, because the mean of its divisors is an integer number (55010059748917).

Almost surely, 2110020119497833 is an apocalyptic number.

It is an amenable number.

110020119497833 is a deficient number, since it is larger than the sum of its proper divisors (1).

110020119497833 is an equidigital number, since it uses as much as digits as its factorization.

110020119497833 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 326592, while the sum is 49.

The spelling of 110020119497833 in words is "one hundred ten trillion, twenty billion, one hundred nineteen million, four hundred ninety-seven thousand, eight hundred thirty-three".