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110020120022081 is a prime number
BaseRepresentation
bin11001000001000000001110…
…001011000000110001000001
3112102112211011022220210201002
4121001000032023000301001
5103410032201211201311
61025554313445421345
732113456065056213
oct3101001613006101
9472484138823632
10110020120022081
11320682a8596615
121040a77770a855
134950b117b0079
141d2500614a5b3
15cabd20c8a93b
hex64100e2c0c41

110020120022081 has 2 divisors, whose sum is σ = 110020120022082. Its totient is φ = 110020120022080.

The previous prime is 110020120021943. The next prime is 110020120022161. The reversal of 110020120022081 is 180220021020011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108384944034481 + 1635175987600 = 10410809^2 + 1278740^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110020120022081 is a prime.

It is a super-2 number, since 2×1100201200220812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (110020120322081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010060011040 + 55010060011041.

It is an arithmetic number, because the mean of its divisors is an integer number (55010060011041).

Almost surely, 2110020120022081 is an apocalyptic number.

It is an amenable number.

110020120022081 is a deficient number, since it is larger than the sum of its proper divisors (1).

110020120022081 is an equidigital number, since it uses as much as digits as its factorization.

110020120022081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 110020120022081 its reverse (180220021020011), we get a palindrome (290240141042092).

The spelling of 110020120022081 in words is "one hundred ten trillion, twenty billion, one hundred twenty million, twenty-two thousand, eighty-one".