Base | Representation |
---|---|
bin | 1010000000011001101100… |
… | …0001001011010101000011 |
3 | 1102221210010010121222201211 |
4 | 2200012123001023111003 |
5 | 2420224110034201313 |
6 | 35222130552110551 |
7 | 2213604054116035 |
oct | 240063301132503 |
9 | 42853103558654 |
10 | 11002012022083 |
11 | 3561a21a67985 |
12 | 129831b695457 |
13 | 61a64021a474 |
14 | 2a070087dc55 |
15 | 1412c3143e3d |
hex | a019b04b543 |
11002012022083 has 2 divisors, whose sum is σ = 11002012022084. Its totient is φ = 11002012022082.
The previous prime is 11002012022063. The next prime is 11002012022149. The reversal of 11002012022083 is 38022021020011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11002012022083 - 217 = 11002011891011 is a prime.
It is not a weakly prime, because it can be changed into another prime (11002012022033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501006011041 + 5501006011042.
It is an arithmetic number, because the mean of its divisors is an integer number (5501006011042).
Almost surely, 211002012022083 is an apocalyptic number.
11002012022083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002012022083 is an equidigital number, since it uses as much as digits as its factorization.
11002012022083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 11002012022083 its reverse (38022021020011), we get a palindrome (49024033042094).
The spelling of 11002012022083 in words is "eleven trillion, two billion, twelve million, twenty-two thousand, eighty-three".
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