110020130213333 has 4 divisors (see below), whose sum is σ = 110020196041920. Its totient is φ = 110020064384748.

The previous prime is 110020130213263. The next prime is 110020130213393. The reversal of 110020130213333 is 333312031020011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110020130213333 - 2²⁴ = 110020113436117 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 110020130213299 and 110020130213308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110020130213393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30340223 + ... + 33772316.

It is an arithmetic number, because the mean of its divisors is an integer number (27505049010480).

Almost surely, 2^{110020130213333} is an apocalyptic number.

It is an amenable number.

110020130213333 is a deficient number, since it is larger than the sum of its proper divisors (65828587).

110020130213333 is an equidigital number, since it uses as much as digits as its factorization.

110020130213333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65828586.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 110020130213333 its reverse (333312031020011), we get a palindrome (443332161233344).

The spelling of 110020130213333 in words is "one hundred ten trillion, twenty billion, one hundred thirty million, two hundred thirteen thousand, three hundred thirty-three".